Not to try and drive all of this off-topic, but HUSH, unless you made some horrid mistake, then you are a bit off on your calculations. With those builds, and the troops you have put down, it would come out like this(the times are for W4 if anyone is wondering(WorkShop=lv.15))...
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Anyway, personally, I would go with several different builds(troops that is) on a fairly simple village build.
HQ - 20
Bar - 25
Stable - 20
WorkShop - 15
Academy - 2(lv. 1 if coin)
Smithy - 20
Rally - 1
Market - 10(I will explain)
All res - 30
Farm - 30
Storage - 30
Hiding Place - 10
Wall - 20
This gives you 20968 farm space left, and 9830 points to a village.
Because of the worlds I play on, I prefer the HC way of things, with techings and all.
So with the builds I have already posted, here are my builds.
Offensive
6018 axes
1665 HC
620 cats
11918 axes
1300 HC
250 rams
11818 axes
1830 rams
For the worlds without the 3-tech system, just switch the HC for LC, and it will work.
Side Note: For those wondering why my builds are like this, I prefer time over anything, though some of these builds may not seem very quick, the others make up for the others.
Now, for those wonder for the level 10 market, here is my explanation of it all...Fairly nice and tidy.
[spoil]Ok, I hope most of you know how to balance resources, with the market, which is a nice idea, but there are other ways to keep everything in check to keep the resources balanced and not really use the market at all.
To begin with, we will look at the troops that would normally be built. By now, most of you know of the 10k/10k or Sp/HC strat for defense. Both are very good, if used well, and to add on, resources are kept at bay. As for offensive units, generally there are axes, LC/HC, and rams/cats.
In both of those, if you check the resources needed for each unit, you can easily find the ones that need what the most. Simple, no?
Well, what do those numbers truly in relation to keeping the resources down low? Well, we will find out through this guide.
I will be looking at the offensive side of things in this.
Alright, so, we have found that the follow units cost a set amount each for each resource:
Unit: wood/clay/iron
Axe: 60/30/40
LC: 125/100/250
HC: 200/150/600
Ram: 300/200/200
Cat: 320/400/100
Alright, so, we have these numbers down, so lets start looking at a nuke, say 8k axes, 2.5k LC, and 400 rams, which is exactly 20k pop.
Axes: 480000/240000/320000
LC: 312500/250000/625000
Rams: 120000/80000/80000
Total: 912500/570000/1025000
Alright, so you have a nice gap between the clay and iron, which is a good thing, because of packets, packets take up more clay than iron. However, look at how lop-sided the resources are. Too much wood is being used, too little of clay is being used, and just enough iron is being used(in ratio to clay).
So, lets try a different build, say 6k axes, 2.9k LC, and 300 cats, to make things interesting.
Axes: 360000/180000/240000
LC: 362500/290000/725000
Cats: 96000/120000/30000
Total: 818500/590000/995000
There, you have a fairly well rounded amount to fit each and every part. Along with this, you also have a nice versatility to it, thanks to the cats. You have just barely over a 400k gap between the clay and iron, which you can eventually fill up with packet costs, so long as you are taking your time with rebuilding the troops, which does not always hold true.
Anyway, so lets look at packets, shall we? 1 packet cost 14000/15000/12500. So, lets look at the difference between clay and wood, and clay and iron. Between clay and wood, there is a gap of 1k, and a 2.5k gap between clay and iron.
Now lets try to balance out the resources completely, shall we?
Alright, so in the last troop build, the difference between wood and clay was 228500, and a 405000 between clay and iron.
Now, lets see how many packets would be needed to be store to balance that, k?
So, lets start with the wood/clay relation.
228500/1000 = 228.5
So, in that respect, you would need 228 packets stored to balance it. Now lets look at how long that would take. So, the resources go up at 3.6k an hour, and the max allowed is 400k. So, 400k/3.6k = 111.1 repeating hours, which equals ~4.6 days, give or take. So, in 4.6 days, you will get max resources, BUT, you do not need max resources, instead, you need only 390000. True, it is not a large difference, but it grows exponentially over time.
So now, we go with 390k/3.6k = 108.3 repeating, which is ~4.5 days, for a completely empty village. So, in ~4.5 days, you can store the max of 26 packets. So, divide the needed packets by 26, which gives you ~8.7, which is the number of times you need to store the max, so, multiply that with the time it takes to get there...Which gives you ~39 days. So a bit more than a month to do. Which isn't bad, but that is just wood-clay.
And now, for the iron...405000/2500 = 162 packets needed, which is less than the wood. So, with that done, all you would truly need to do is go by the wood-clay ratio, and build off of it until the resources are balanced.
So, just to rap it all up, lets do a quick resource add-up on the packets and troops.
So, packets were a need of 228, so it would be 3192000/3420000/2850000, now add the troop resources, which were 818500/590000/995000.
So it would be a grand total of:
4010500/4010000/3845000.
See how it all came together nicely? It saves you time from having to go through all your markets to rebuild every so often, and, even if you rebuild the troops more often than 39 days, it would probably bring it closer to balance.
You can fiddle around with the axes - LC(or HC) ratio, until the packet need get to be very close to balanced, this was just a demonstration as to how it works, to get everything in balance.
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I have no idea for a coin world, so you can attempt at figuring it out if you want. Also, this is at half price nobles, so just cut the time in half for the newer worlds(cost = x2).